If $u(z) = \frac{7 \ln(z)}{(\frac{1}{z})}$, then: a) $u'(z) = \frac{\frac{7}{z^2} - \frac{7 \ln(z)}{z^2}}{(\frac{1}{z^2})}$ b) $u'(z) = 0$ c) $u'(z) = \frac{\frac{7}{z^2} + \frac{7 \ln(z)}{z^2}}{(\frac{1}{z^2})}$ d) $u'(z) = \frac{14}{z^2 (\frac{1}{z^2})}$
Added by Colton M.
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Step 1: Simplify u(z): u(z) = (7 ln(z)) / (1/z) = 7 ln(z) * z = 7 z ln(z). Show more…
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