If we dissolve 0.4505 g of CaCO3 in HCl and dilute to 250 mL,
measure out 25 mL of this solution and titrate it with EDTA
solution. It takes 24.25 mL of EDTA solution to the titration end
point. (a) How many moles of CaCO3 present in its solution? (b)
What is the [Ca2+] in its solution? (c) How many moles of EDTA
present in 24.25 mL of its solution? (d) What is the [EDTA] in its
solution?