If y = tan^(-1)(cos(2u)), u = cos^(-1)(x) and t = ln(x), then dy when x = ve is dx.
Added by Dana G.
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Step 1
First, we need to find the value of cos(2u) when u=cos^-1(0). Since cos(2u) = 2cos^2(u) - 1, we have cos(2u) = 2(0)^2 - 1 = -1. Show more…
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