00:01
So we're looking at a genetic cross here.
00:03
I'll have parent one, which is a -a -b -v -c, crossed with parent -2, and we want all of the outcomes that have a particular genotype.
00:12
Okay, first thing i'm going to do is work out how many gabbats are on.
00:16
So you get a multiple of two for each heterozygous locus.
00:23
So it's 2 to the power of n, where n equals the number of heterozygous.
00:31
Lopi.
00:32
So parent one has two heterozygous loci.
00:36
So they have four gametes.
00:38
And they would look like this.
00:46
Same for parent two.
00:53
These are their gametes.
00:54
So i've just gone through all the combinations, knowing that these are all going to be capital a, these are all going to be little c.
01:01
Okay.
01:03
So there are four gametes of each parent, which means there will be 16 offspring genocytes.
01:10
Some might be repeats, we haven't looked into that yet, but if we were to do a punnet square here, we would have 16 squares, because it would be four along the top, four along the side, four squared.
01:21
We are looking for a particular genotype in the offspring.
01:28
Next, what i'm going to do is i'm going to see which of these combinations would actually give me this, because i see i have two b allios here, but are both dominant, so the gametes that lead to this cannot possibly have a little b.
01:43
So this one here, and this one here, this one here, this one here, cannot lead to it.
01:51
So if i label these and do a mini -punit square, i will show you what i mean.
02:03
So if i have a, b, c and d along the top, e, f, g, and h along the sides, okay, so if you were to do a punnet square and you would fill it all out, it would kind of take a while.
02:24
This is going to be faster.
02:26
So i can see that b has a little b...