If you have a manometer with a 50cm tall water column, what is the largest pressure that can be measured? Assume that the densities of water and mercury are 1000 kg/m3 and 13 600 kg/m3 respectively
Added by Savisesh R.
Step 1
First, we need to find the height of the mercury column that would be equivalent to the 50 cm water column. To do this, we can use the formula: h_mercury = (density_water / density_mercury) * h_water Show more…
Show all steps
Your feedback will help us improve your experience
Satish Kumar and 66 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Calculate, in kPa, the pressure exerted by a column of water that is 10-m tall. Assume the weight density of water to be $10,000 \mathrm{N} / \mathrm{m}^{3},$ and ignore the pressure due to the atmosphere.
The difference in height between the columns of a manometer is $200 \mathrm{mm}$ with a fluid of density 900 $\mathrm{kg} / \mathrm{m}^{3} .$ What is the pressure difference? What is the height difference if the same pressure difference is measured using mercury (density $=13600 \mathrm{kg} / \mathrm{m}^{3}$ ) as manometer fluid?
If $1 \mathrm{m}^{3}$ of water has a mass of $1000 \mathrm{kg},$ what is the pressure at a depth of $150 \mathrm{m} ?$ Is the atmospheric pressure important?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Watch the video solution with this free unlock.
EMAIL
PASSWORD