If \( y=\sec x \), prove that \( y \frac{\mathrm{~d}^{2} y}{\mathrm{~d} x^{2}}=\left(\frac{\mathrm{d} y}{\mathrm{~d} x}\right)^{2}+y^{4} \)
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\[ \frac{\mathrm{d} y}{\mathrm{d} x} = \frac{\mathrm{d}}{\mathrm{d} x} (\sec x) = \sec x \tan x = y \tan x \] Show more…
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