00:02
Okay, so when a circuit like this, we see that there are two batteries that are connected and then we have three resistors.
00:12
Now we always, when we have to use kirchap's law here because it's a complicated circuit, we have two batteries.
00:21
And that kirchap's law has two sections.
00:24
We'll start with junction rule and then we'll do the loop rule.
00:28
So when we start with junction rule, what that tells us is first we need to find out a junction.
00:37
So for example, we have two junctions here.
00:41
And let's consider one of the junctions.
00:43
So for this problem, i'm taking this one as the junction that i'm applying my rule.
00:52
Now, what this junction rule tells us is if there's a current that is going out, of the junction that should be equal to the currents that are coming towards the junction.
01:04
So we see that i2 is going out and i3 and i1 are coming in.
01:10
So that means our if we want to apply the rule it's going to be i2 equals to i1 plus i3.
01:24
So that's we found that using our junction rule.
01:30
Now we could have used this junction again because we have to consider all the junctions to use our rule but as you can see that in this area the i2 is coming towards the junction and then i chain i one are going out so it's gonna give you the same expression like this so we don't need to do this for this example but there might be other examples where we might need to use all the junctions okay, so now we'll use the loop rule.
02:02
So for loop rule what we know is if there's a potential drop then there will be a negative sign and if there's a potential gain then there's a positive sign so that's one thing to remember and the other one that we should remember or which will simplify our problem is if we consider the direction of our loop so let's consider this loop and let's take clockwise direction as our direction.
02:31
So if the current goes with the direction that we specify, then there will be a negative sign...