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In #17-18, find an equation of the tangent plane to the given surface at the specified point. 17. $z = \cos(2x+y)$, $\left(\frac{\pi}{2}, \frac{\pi}{4}, -\frac{1}{\sqrt{2}}\right)$ 18. $z = x^3 - 3xy + y^3$, $(1, 2, 3)$

          In #17-18, find an equation of the tangent plane to the given surface at the specified point.
17. $z = \cos(2x+y)$, $\left(\frac{\pi}{2}, \frac{\pi}{4}, -\frac{1}{\sqrt{2}}\right)$
18. $z = x^3 - 3xy + y^3$, $(1, 2, 3)$

In #17-18, find an equation of the tangent plane to the given surface at the specified point.
17. z = cos(2x+y), ((π)/(2), (π)/(4), -(1)/(√(2)))
18. z = x^3 - 3xy + y^3, (1, 2, 3)

Added by Lynn L.

Calculus: Early Transcendentals

James Stewart 8th Edition

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03/30/2024

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Step 1: The equation of the tangent plane to the surface z = f(x, y) at the point (x0, y0, z0) is given by: z - z0 = f_x(x0, y0)(x - x0) + f_y(x0, y0)(y - y0) Show more…

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In #17-18, find an equation of the tangent plane to the given surface at the specified point. 17. z = cos(2x+y), (π/2, π/4, 1/√2) 18. z=x³-3xy + y³, (1,2,3)

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In #17-18, find an equation of the tangent plane to the given surface at the specified point. 17. $z = \cos(2x+y)$, $\left(\frac{\pi}{2}, \frac{\pi}{4}, -\frac{1}{\sqrt{2}}\right)$ 18. $z = x^3 - 3xy + y^3$, $(1, 2, 3)$

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