In a certain population of mice a single gene controls fur...

In a certain population of mice, a single gene controls fur color. There are two possible alleles: B, which leads to a black fur, and W, which leads to white fur. Individuals with the genotype BB will have a black fur, individuals with the genotype WW will have white fur, and individuals with the genotype BW will have gray fur. Scientists recorded the fur color of 1,000 mice from the population. They found that 200 mice have black fur, 400 have gray fur, and 400 have white fur. Ten years later, the measurements are repeated. Again, they recorded the fur color of 1,000 mice. They found that 400 have black fur, 400 have gray fur, and 200 have white fur. Part A: Show the Hardy-Weinberg calculations for the beginning and ending populations. Include the values for the equation as well as the p and q values. Show your work. Part B: Use the Hardy-Weinberg calculation to explain if this population is evolving or not. Then propose a hypothesis about the environment of these mice that would lead to these observations.

Transcript

00:01 In order to answer this question, let's talk about hardy wayburn.

00:03 It says, in a certain population of mice, a single gene controls four color.

00:07 There are two possible at least, b, which leads to black fur and w, which leads to white fur.

00:13 Individuals with a genotype homocygot for w called for black, individuals with a homocygose for w gives white, and the heterocygose gives gray.

00:32 So it says, scientists recorded a four color.

00:35 Of 1 ,000 mice from the population, so you have a total of 1 ,000 mice.

00:41 They found that 200 mice have black, so it means 200 have black.

00:48 They will just like this.

00:49 200 have black, 400 gray, and the remaining 200 white.

00:56 This is what you have.

00:58 And it says, 10 years later, the measurements i repeated, again, they reported the full color of 1 ,000 mice.

01:06 So you have again 1 ,000 miles where 400 have black four 400 half black four 400 half gray four and only 200 half white four part a show the harding wehber calculations for the beginning and ending populations include the values for the equation as well as the p and q values and show your work so let's find the p and q values here remember that according to p according to harding wenberg p plus q is equal to 1, where p is the frequency of alilis in the population, that b alis, and q for the w alis.

01:44 You also have that p square plus 2pq plus q plus q squared is equal to 1, where p square is a frequency of homocygose for b, 2 pq is a frequency for heterocygote, and q square is a frequency for homozygosephoidal for w.

02:00 In this case, what is the frequency for homozygosegose dominant? or for homozygosegose for b, you have 200, are of the total because it is a frequency.

02:12 You have to divide by the total, okay? so you have 200 divided by 1000.

02:17 So this is equal to 0 .2.

02:21 Now for q, for the homo -sigo per average you have also 200 divided by 1000.

02:27 So you have here 0.

02:31 And for the heterocyles, you have 400 divided by 1 ,000, that is 0 .4.

02:37 But this 0 .4, you're going to divide this 0 .4 in 1 .5.

02:44 Half.

02:45 Okay? why? well, because each hydrosygos has one dominant or one b allele and one y allele.

02:51 And we want to group only the b alleles to the left and only the wllls to the right.

02:56 Okay, so in this case, you are going to have 0 .2 and 0 .2.

03:01 And this is how you're going to group...