Given: Charge of electron, $q = 1.6 \times 10^{-19} \, \text{C}$, Electric field, $E = 3.0 \times 10^{4} \, \text{V/m}$.
The electric force, $F_E = q \times E = 1.6 \times 10^{-19} \times 3.0 \times 10^{4} = 4.8 \times 10^{-15} \, \text{N}$.
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