In a large randomly mating population, 0.84 of the individuals express the phenotype of the dominant allele A and 0.16 express the phenotype of the recessive allele a. If the aa homozygotes are 10% less fit than the other genotypes, what will be the frequency of homozygotes in the next generation?
Added by Jose Luis N.
Step 1
First, we need to find the frequency of the dominant allele (A) and the recessive allele (a) in the population. We know that 0.84 of the individuals express the dominant phenotype, which means they have either AA or Aa genotypes. We also know that 0.16 of the Show more…
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20.20 In a large randomly mating population, 0.84 of the individuals express the phenotype of the dominant allele A and 0.16 express the phenotype of the recessive allele a. (a) What is the frequency of the dominant allele? (b) If the aa homozygotes are 5 percent less fit than the other two genotypes, what will the frequency of A be in the next generation?
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In a population in Hardy-Weinberg equilibrium, the frequency of the recessive homozygous genotype (q^2) is 0.16 and the frequency of a dominant phenotype (p^2 + 2pq) is 0.84. What is the expected frequency of the heterozygous carriers (2pq)? explain please
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