Question

In a nuclear experiment a proton with kinetic energy 0.80 MeV moves in a circular path in a uniform magnetic field. What energy must (a) an alpha particle (q = +2e, m = 4.0 u) and (b) a deuteron (q = +e, m = 2.0 u) have if they are to circulate in the same circular path?

Name: in a nuclear experiment a proton with kinetic energy 080 mev moves in a circular path in a uniform magnetic field what energy must a an alpha particle q 2e m 40 u and b a deuteron q e m 20 u 86037
Uploaded: 2022-06-15T12:20:54-08:00
Duration: 2 min 18 s
Channel: Shaiju T
Description: in a nuclear experiment a proton with kinetic energy 080 mev moves in a circular path in a uniform magnetic field what energy must a an alpha particle q 2e m 40 u and b a deuteron q e m 20 u 86037

          In a nuclear experiment a proton with kinetic energy 0.80 MeV
moves in a circular path in a uniform magnetic field. What energy
must (a) an alpha particle
(q = +2e, m = 4.0 u)
and (b) a deuteron (q =
+e, m = 2.0 u) have if they are to circulate in the same
circular path?

Added by Jacob R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Shaiju T

06/15/2022

Step 1

Given: Charge of alpha particle, q_alpha = +2e Mass of alpha particle, m_alpha = 4.0 u Using the formula K_alpha = K_proton * (q_alpha/q_proton)^2 * (m_proton/m_alpha) Substitute the values: K_alpha = 0.80 MeV * (2/1)^2 * (1/4) K_alpha = 0.80 MeV * 4 * Show more…

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In a nuclear experiment a proton with kinetic energy 0.80 MeV moves in a circular path in a uniform magnetic field. What energy must (a) an alpha particle (q = +2e, m = 4.0 u) and (b) a deuteron (q = +e, m = 2.0 u) have if they are to circulate in the same circular path?