00:01
Hello students, here one ic design is given with the length 2 micrometer, current of the device is let us consider this as i naught which is 100 micro ampere and omega by l ratio is 5, initial resistor value which is considered as r naught will be 0 .5 mega ohm.
00:29
Now, one -fourth of this design must be obtained.
00:35
For that we need to change the dimensions, we need to find the changed dimensions here.
00:42
Initially for this we know that voltage is given by current multiplied with resistor.
00:52
Now, multiplying 0 .5 into 100 we obtain voltage as 50 volt, here mega and micro get cancelled.
01:05
Then about changing dimension, first we need to change resistor value.
01:13
As we need one -fourth of the configuration, we need to multiply 4 with the given resistor value.
01:23
There we get initial 0 .5 mega ohm, then changed dimension is 2 mega ohm.
01:29
From this voltage is also changing which is multiply newly obtained resistor with current.
01:39
Current will remain constant, so substituting for current as 100 itself we get 200 volt.
01:46
Now, we know that voltage is proportional to length...