4. In a population of 10,000 individuals, where 3600 are MM,...

4. In a population of 10,000 individuals, where 3600 are MM, 1600 are NN, and 4800 are MN, what are the frequencies of the M alleles and the N alleles? 5. Assuming that p = 0.3 for a population in Hardy-Weinberg equilibrium, what would be the expected frequency of heterozygotes for the involved allelic pair? 6. A certain form of albinism in humans is recessive and autosomal. Assume that 1% of the individuals in a given population are albino. Assuming that the population is in Hardy-Weinberg equilibrium, what percentage of the individuals in this population is expected to be heterozygous?

Transcript

00:01 Here in the first question, the total population given is 10 ,000 and the genotype population of the capital m, capital m, that is 3 ,600.

00:26 And the heterozygous condition, mn has the population 4 ,800.

00:34 And the homozygous condition, capital n, capital n.

00:40 This has 1600.

00:43 So here, as per the hardy -winberg equilibrium formula, we can say that the frequency of the allele m, these can be considered as the p.

01:00 This will be here 2 into the population of m, that is 3 ,600 plus the population of mn, that is 4 ,800, that is 4 ,800 ,000.

01:19 By 2 into the total population that is 10 ,000 and this here will be equal to 0 .6 and the frequency of the allel n can be considered as q this is equal to 2 .2 into the n population that is 1 ,600 plus 4 ,800 the mn and this is divided by 2 into the total population 10 ,000, that is equal to 0 .4.

02:06 So these are our first answer.

02:09 In the next question we have to assume that the population is in hardy -winberg equilibrium.

02:19 Here we know as per the hardy -win -bar equilibrium, p plus q is equal to 1.

02:26 Now, p given here is 0 .3.

02:31 So, q will be 1 minus p that is equal to 1 minus 0 .3, that is equal to 0 .7.

02:45 So, here the heterozygous frequency, these heterozygous frequency as per herdy wienberg equilibrium is equal to 2p.

03:02 So here 2p .cube will be 2 into 0 .3 into 0 .7, that is equal to 0 .42...

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