In a survey of 2949 adults, 1405 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is (___,___) ROUND TO THREE DECIMAL PLACES AS NEEDED.
Added by Lorena G.
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p̂ = 1405 / 2949 = 0.4761 n = 2949 Show more…
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In a survey of 3188 adults, 1429 say they have started paying bills online in the last year Construct a 99% confidence interval for the population proportion. Interpret the results . A 99% confidence interval for the population proportion is (Round to three decimal places as needed).
In a survey of 2783 adults, 1418 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is. (Round to three decimal places as needed.)
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