In an electric motor, a coil with 100 turns of radius 2.0 cm can rotate between the poles of a magnet. The magnetic field magnitude is 0.20 T. When the current through the coil is 50.0 mA, what is the maximum torque that the motor can deliver?
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We know that the torque τ on a current-carrying loop in a magnetic field is given by the formula: τ = n * B * A * I * sin(θ) where n is the number of turns, B is the magnetic field magnitude, A is the area of the loop, I is the current, and θ is the angle Show more…
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