Question
In an electric motor, a circular coil with 100 turns of radius $2.0 \mathrm{cm}$ can rotate between the poles of a magnet. When the current through the coil is $75 \mathrm{mA}$, the maximum
Step 1
We know that 1 cm = 0.01 m. So, the radius of the coil in meters is $2.0 \times 0.01 = 0.02$ m. Show more…
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In an electric motor, a coil with 100 turns of radius $2.0 \mathrm{cm}$ can rotate between the poles of a magnet. The magnetic field magnitude is $0.20 \mathrm{T}$. When the current through the coil is $50.0 \mathrm{mA},$ what is the maximum torque that the motor can deliver?
In an electric motor, a coil with 100 turns of radius $2.0 \mathrm{cm}$ can rotate between the poles of a magnet. The magnetic field strength is $0.20 \mathrm{T}$. When the current through the coil is $50.0 \mathrm{mA},$ what is the maximum torque that the motor can deliver?
In an electric motor, a coil with 100 turns of radius 2.0 cm can rotate between the poles of a magnet. The magnetic field magnitude is 0.20 T. When the current through the coil is 50.0 mA, what is the maximum torque that the motor can deliver?
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