00:01
We are given volume 250 ml concentration 0 .6 molar for sodium sulfate for barium chloride.
00:19
Volume given is 300 ml concentration is 0 .45 molar.
00:26
In the given reaction, sodium sulfate reacts with barium chloride and sodium chloride plus barium sulfate.
00:44
Where barium sulfate is the precipitate on which we have to find the mass.
00:53
First of all, we will find the moles of sodium sulfate which is equal to concentration into into volume in liters so it will be 0 .6 into 250 divided by 1000 liters which is equal to 0 .15 moles.
01:19
Moles of barium chloride will be equal to concentration into volume in liters that is equal to 0 .135 moles.
01:34
From the reaction, we can see that one mole of sodium sulfate requires one mole of barium chloride.
01:49
There are current simple terms.
01:52
Barium chloride has less moles than sodium sulfate which makes barium chloride a limiting the reaction of the reaction is the presence of barium chloride.
02:17
The one mode of barium chloride is one mode of barium sulphate.
02:23
Therefore, 0 .137 moles of barium chloride is also there.
02:28
0 .135 moles of barium sulphate.
02:33
The molar mass of barium sulfate will be equal to the molar mass of barium, which is 137 kilos, salt for 32, and salt for 16 for oxygen...