Question

In an NPN transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, the emitter current (i E ) and base current (i B ) are given by (a) i E = – 1 mA, i B = 9 mA (b) i E = 9 mA, i B = – 1 mA (c) i E = 1 mA, i B = 11 mA (d) i E = 11 mA, i B = 1 mA

Name: in an npn transistor circuit the collector current is 10 ma if 90 of the electrons emitted reach the collector the emitter current i e and base current i b are given by a i e 1 ma i b 9 ma b i e 9 ma
Uploaded: 2022-02-05T06:52:55-08:00
Duration: 1 min 38 s
Channel: Deepak Jangra
Description: in an npn transistor circuit the collector current is 10 ma if 90 of the electrons emitted reach the collector the emitter current i e and base current i b are given by a i e 1 ma i b 9 ma b i e 9 ma

          In an NPN transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, the emitter current (i E ) and base current (i B ) are given by (a) i E = – 1 mA, i B = 9 mA (b) i E = 9 mA, i B = – 1 mA (c) i E = 1 mA, i B = 11 mA (d) i E = 11 mA, i B = 1 mA

Added by Ashu G.

Master Resource Book in JEE Main Physics

D. B. Singh 1st Edition

Chapter 26

Instant Answer

Solved by Expert Deepak Jangra

02/05/2022

Step 1

9 * i_E Substitute the values: 10 mA = 0.9 * i_E i_E = 10 mA / 0.9 i_E = 11.11 mA Show more…

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In an NPN transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, the emitter current (i E ) and base current (i B ) are given by (a) i E = – 1 mA, i B = 9 mA (b) i E = 9 mA, i B = – 1 mA (c) i E = 1 mA, i B = 11 mA (d) i E = 11 mA, i B = 1 mA