In an $n-p-n$ transistor, the collector current is $10 \mathrm{~mA}$, if $90 \%$ of the electrons emitted reach the collector, the emitter current $\left(I_{E}\right)$ and base current $\left(I_{B}\right)$ are given by
(a) $I_{E}=-1 \mathrm{~mA}, I_{b}=9 \mathrm{~mA}$
(b) $I_{E}=9 \mathrm{~mA}, I_{B}=-1 \mathrm{~mA}$
(c) $l_{E}=1 \mathrm{~mA}, l_{B}=11 \mathrm{~mA}$
(d) $I_{E}=11 \mathrm{~mA}, I_{B}=1 \mathrm{~mA}$