For the first subspace, we have vectors of the form (a, b, c) where c = 5a + 2b. We can rewrite this as (a, b, 5a + 2b). Now, we can factor out the scalars a and b to get a(1, 0, 5) + b(0, 1, 2). So, the basis for this subspace is {(1, 0, 5), (0, 1, 2)}, and its
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