Question

In Exercises 25-28, evaluate the given functions. The values of the independent variable are approximate. 25. Given $f(x) = 5x^2 - 3x$, find $f(3.86)$ and $f(-6.92)$. 28. Given $f(x) = \frac{x^4 - 2.0965}{6x}$, find $f(1.9654)$.

          In Exercises 25-28, evaluate the given functions. The values of the independent variable
are approximate.
25. Given $f(x) = 5x^2 - 3x$, find $f(3.86)$ and $f(-6.92)$.
28. Given $f(x) = \frac{x^4 - 2.0965}{6x}$, find $f(1.9654)$.

Added by Stephanie F.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Abhijith V

06/05/2021

Step 1

86)$, substitute $x = 3.86$ into the function $f(x) = 5x^2 - 3x$. Show more…

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In Exercises 25□-28□, evaluate the given functions. The values of the independent variable are approximate. 25. Given $f(x) = 5x^2 - 3x$, find $f(3.86)$ and $f(-6.92)$. 28. Given $f(x) = \frac{x^4 - 2.0965}{6x}$, find $f(1.9654)$.