Question

In Exercises 39-46, determine the intervals over which the function is increasing, decreasing, or constant. $ f(x) = \left\{ \begin{array}{ll} x+3, & \mbox{ $ x \le 0 $} \\ 3, & \mbox{ $ 0 < x \le 2 $} \\ 2x+1, & \mbox{ $ x > 2 $} \end{array} \right.$

Name: in exercises 39 46 determine the intervals over which the function is increasing decreasing or constant fx left beginarrayll x3 mbox x le 0 3 mbox 0 x le 2 2x1 mbox x 2 endarray right 2
Uploaded: 2021-09-06T20:18:06-08:00
Duration: 2 min 51 s
Channel: Teresa Fuston
Description: in exercises 39 46 determine the intervals over which the function is increasing decreasing or constant fx left beginarrayll x3 mbox x le 0 3 mbox 0 x le 2 2x1 mbox x 2 endarray right 2

          In Exercises 39-46, determine the intervals over which the function is increasing, decreasing, or constant.

$ f(x) = \left\{
          \begin{array}{ll}
              x+3,  & \mbox{ $ x \le 0 $} \\
              3,  & \mbox{ $ 0 < x \le 2 $} \\
              2x+1,  & \mbox{ $ x > 2 $}
           \end{array} \right.$

Added by Peter B.

Precalculus with Limits

Ron Larson 2nd Edition

Chapter 1

Instant Answer

Solved by Expert Teresa Fuston

09/06/2021

Step 1

- For $0 < x \leq 2$, the function $f(x) = 3$ is constant. - For $x > 2$, the function $f(x) = 2x + 1$ has a positive slope, so it is increasing. ** Show more…

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In Exercises 39-46, determine the intervals over which the function is increasing, decreasing, or constant. $ f(x) = \left\{ \begin{array}{ll} x+3, & \mbox{ $ x \le 0 $} \\ 3, & \mbox{ $ 0 < x \le 2 $} \\ 2x+1, & \mbox{ $ x > 2 $} \end{array} \right.$