In glycolysis the km of hexokinase is 004 mm under...

In glycolysis, the KM of hexokinase is 0.04 mM. Under physiological conditions, the glucose concentration at the cellular level is between 4 mM to 15 mM. Based on this information, which of the following is true of hexokinase under physiological conditions? (MULTIPLE ANSWER) a. Hexokinase is saturated with its substrate b. The enzyme works at its Vmax c. Such a low KM value ensures that the glycolysis process will continue even when the glucose level drops to its lowest level of 4 mM. d. The enzyme has low affinity for its substrate e. Glucose phosphorylation occurs slowly

Transcript

00:01 So what is given in this question is we are given some information regarding glycolysis process.

00:06 Glycolysis.

00:07 So what is given in this question is that the km value of enzyme hexokinness which is used in glycolysis process.

00:15 Okay.

00:16 Km value for enzyme hexokinines is given to us and this value is 0 .04 millimolar.

00:23 This is the value of km which is given.

00:25 And another information which is mentioned here already that you can all say it.

00:30 Set as by default that it is all around physiological condition that means ph will be around 7 ph will be around 7 the temperature will be around 37 degrees celsius so that enzyme can work at their best okay this is the value which is given to us another point which is given to us about this is that glucose concentration at cellular level so concentration or glucose is given to us at cellular level and this concentration of glucose is between 4 millimolar to 15 millimolar.

01:05 This is a value which is given to us about glucose concentration at cellular level.

01:11 So what we have to understand what we have to find is which of the following statement is true for hexokinous enzyme.

01:17 We have to identify the true statement.

01:20 Okay.

01:21 So according to the michael's method equation, what is it say that v0, that is velocity is equals to v -machyman.

01:27 V max plus v max v max into substrate right into substrate concentration upon km value plus s.

01:38 This is the michaelis menter equation which is given to us.

01:40 Now look at the values of these which is given to us because if values are given to us that there might be some role.

01:47 Otherwise there is no need for the extra information that they will give it just to confuse us.

01:52 There is a information which is given to us indirectly.

01:55 And what is this equation information which is given to us.

01:57 That s, the s, that is the substrates, is very, very, very less than km, right? this is the point we have to understand from here is that the substrate, the glucose at which reaction is being carried out, has a concentration much, much, much larger than the km of the hexokinous because we can clearly see that it is around 50 millimolar, but it is only around 0 .04 millimolar.

02:21 So we have to interpretate this information by observing the question, right? so it is given to us...

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