00:01
In order to answer this question, let's talk about hardy -weibber equilibrium.
00:03
It says in a given population, 16 % of the population has blue eyes and 84 has brown eyes.
00:09
Also, eye color is a polygenicrate.
00:11
Let's assume for this problem that the brown is dulled to the blue -eyed allil.
00:16
So you have, this is the brown -eye allele.
00:20
Brown -eye -allel.
00:21
This is a blue -eye allele.
00:23
So according to hardy -weenberg, when you have p -plus -q, it is equal to 1.
00:28
This is p -plus -k, okay? p plus q, where p is the frequency of alils in the population that are dominant alils, and q is the frequency of alils in the population that are recessive alils.
00:37
You also have that p squared plus 2 pq plus q squared is equal to 1, where p.
00:43
Square is the frequency of homozygous dominant in the population.
00:46
2pq is the frequency of individuals in the population that are hydrocygous, and q is the frequency of individuals in the population that are homozygous decisive.
00:54
So, it says that 84 % has browned ice, it means.
01:03
The homozygoyose dominant and the heterocygos are going to be 84%.
01:07
And it means that only 16 % are going to be homozygoc recessive.
01:13
So as the frequency for homozygous recessive is u squared, then it means that q square is equal to 16%.
01:19
And 16 % is the same as 16 divided by 100.
01:23
So you can keep solving this and you're going to get 0 .16.
01:27
If you divide 16 by 100, and if you apply good square here and also here, you're going to get that q is equal.
01:33
To 0 .4.
01:36
And also as p plus q is equal to 1 and q is 0 .4, then it means that p is equal to 0 .6.
01:43
So it says, what are the gene frequencies for brown -eyed and brown -eyed alleles? so brown -eyed allele frequency, they're asking you for the dominant allele, it means for the value for p.
01:55
And the value for p is 0 .6.
02:00
It is not 0 .9.
02:02
I think that what you are doing or what you are was this p squared is equal to 84 % that is practically 0 .84 okay in 0 .84 if you apply with a square you're going to get approximately 0 .9 but this is not correct because remember that it says that 84 % has brown eyes but brown eyes is not only homozygous dominant also heterocygous okay so the homozygous dominant and the heterocygous as both have one dominant allele then both are going to quote for the brown phenotype but in this case of the homoselyly excessive you're going to code for blue eyes.
02:39
This is the only possibility for blue eyes...