00:01
Not yet to answer this question, let's talk about harding -weber equilibrium.
00:04
It says, according to hardy -weenberg, p plus q is equal to 1, where p is the frequency of alleleys in the population that are dominant allele.
00:14
In this case, let's use the r -aline, okay, this is the dominant allele, and q is the frequency of alleles in the population that are recessive allings.
00:22
Also, you have that p -square plus 2 -p -q plus q -square is equal to 1, where b square is the frequency of individuals in the population that are homoseid dominant, 2 pq is the frequency of individuals in the population of are heterogeneous cybor, nqsquare is the frequency of the population of the formosidio -recessive.
00:42
So let's answer that question.
00:43
And this question number one says, what is the hardy -weimber symbol for the frequency of the dominant allele and the answer for question one in whom to be p, okay? as you can see here, this is for the frequency for the dominant allele.
00:56
Now let's hope for question two.
00:59
It says, what is the hard for the reminder symbol for the frequency of the recessivealy and it is going to be q.
01:05
Okay, q.
01:07
I have q here.
01:08
Now, i'll go for question number three.
01:13
Question number three says, what is the hard helper symbol for the frequency of the hystrosygo genotype? and it is going to be 2pq.
01:22
Question number four says, what is the hard framework symbol for the frequency of the homozygousous dominant and it is going to be p .square.
01:31
Question 5 says, what is the harddenberg symbol for the frequency of the homozygo's recessive genotype and this is going to be q square.
01:39
Question 6 says if the allele frequency of the of the recessive r is 0 .7, it means you have that q is equal to 0 .75.
01:50
What is the allele frequency for the dominant r? remember that p plus q has to be equal to 1.
01:56
And if you is equal to 0 .75, then p is going to be the remaining number that is going to add to this number in order to get 1.
02:04
So you're going to get 0 .25.
02:07
Because if you add these two numbers, we're going to get 1.
02:11
Okay, so this is the answer for question 6, 0 .25.
02:15
Question 7 says, if the elite frequency of the dominant r is 0 .15, it means 0 .15.
02:27
What is the lead frequency of the recessive r? it means the value for q.
02:31
And you're going to have that this is going to be 0 .85.
02:34
Okay, so this is going to be 0 .85.
02:38
Now, question a, that says, in a population, the homozygous dominant individuals make up 81 % of the population.
02:48
Hitrocygid individuals make 18 % in homozygo recessive.
02:53
So, they are telling you that in a population, the homocylus dominant, so they are specifying, they are not telling you the dominant phenotype.
03:03
They are telling you, or they are specifying you specifically the homozygous dominant genotype.
03:07
So they are talking about p square.
03:10
Individuals make up 801 % on a population.
03:13
And they are asking you what is the frequency of a p allele.
03:15
So you have that p square is going to be equal to to 81%.
03:21
That is 0 .80 .81...