Question

In order to test a hypothesis: Ho: μ = 5, Ha: μ < 5, a sample of subjects was randomly selected. Suppose the population is normally distributed with σ = 0.92 mg/l. a) Compute the power of the test (α = 0.05) if the sample size is 60 and the true mean is 4.75. b) Compute the power of the test if (α = 0.1) if the sample size is 45 and the true mean is 4.75. 

          In order to test a hypothesis:
Ho: μ = 5, Ha: μ < 5, a sample of subjects was randomly selected. Suppose the population is normally distributed with σ = 0.92 mg/l. 
a) Compute the power of the test (α = 0.05) if the sample size is 60 and the true mean is 4.75.
b) Compute the power of the test if (α = 0.1) if the sample size is 45 and the true mean is 4.75.
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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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In order to test a hypothesis: Ho: μ = 5, Ha: μ < 5, a sample of subjects was randomly selected. Suppose the population is normally distributed with σ = 0.92 mg/l. a) Compute the power of the test (α = 0.05) if the sample size is 60 and the true mean is 4.75. b) Compute the power of the test if (α = 0.1) if the sample size is 45 and the true mean is 4.75.
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Transcript

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00:01 In this question for solution of a part, we are given that n is equal to 14, mu is equal to 69 and our sigma is equal to 90.
00:11 So for sample size 14, we will check our probability for getting x par less than 72 .4.
00:19 So that is equal to the shaded reason where we can plot this as this is a curve.
00:29 And here we have our value for mu which is 69 and this is the value for bar x is equal to 72 .4.
00:40 So the shaded reason will be the complete reason over here.
00:45 This will be the shaded reason.
00:48 And now we will find our z which is x bar minus mu divided by sigma for the divided by square root of it.
00:55 So we can calculate that as 72 .4 minus 69 divided by sigma which is 19 further divided by square root of 40.
01:08 So we will get here 0 .6696.
01:15 This is a z value.
01:17 So that required area from left of z, that is equal to 0 .6696 and it is equal to 0 .7485.
01:39 So here's the solution.
01:41 The first part of the question...
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