In proton beam therapy, a high energy beam of protons is fired at a tumor. As the protons stop in the tumor, their kinetic energy breaks apart the tumor's DNA, thus killing the tumor cells. For one patient, it is desired to deposit 0.1 J of proton energy in the tumor. The proton beam is created by accelerating protons from rest through a 10000 kiloVolt potential difference. (a) What is the total charge of the protons that must be fired at the tumor for this patient? (b) How many protons deposited their energy in the tumor? (c) What is the kinetic energy in Joules of one proton after passing through the potential difference?
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Given: Energy (E) = 0.1 J Potential difference (V) = 10,000 kV = 10,000 x 10^3 V We know that E = QV, where Q is the total charge. Therefore, Q = E/V = 0.1 / (10,000 x 10^3) = 1 x 10^-8 C Show more…
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In proton-beam therapy, a high-energy beam of protons is fired at a tumor. The protons come to rest in the tumor, depositing their kinetic energy and breaking apart the tumor's DNA, thus killing its cells. For one patient, it is desired that 0.10 J of proton energy be deposited in a tumor. To create the proton beam, the protons are accelerated from rest through a 16 MV potential difference. Part A What is the total charge of the protons that must be fired at the tumor to deposit the required energy? Express your answer with the appropriate units.
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Proton-beam therapy is a treatment method where a high-energy beam of protons is fired at a tumor. As the protons stop in the tumor, their kinetic energy breaks apart the tumor's DNA, thus killing the tumor cells. For one patient, it is desired to deposit 0.10 J of proton energy in the tumor. To create the proton beam, protons are accelerated from rest through a 1.1x10^4 kV potential difference. Part A: What is the total charge of the protons that must be fired at the tumor? Express your answer to two significant figures and include the appropriate units.
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A high-energy accelerator produces a beam of protons with kinetic energy 2 Gev (that is, $2 \times 10^{9}$ ev per proton). The current is 1 milliamp. The beam diameter is $2 \mathrm{~mm}$. As measured in the laboratory frame: (a) What is the strength of the electric field caused by the beam $1 \mathrm{~cm}$ from the central axis of the beam? (b) What is the strength of the magnetic field at the same distance? Now consider a frame $F^{\prime}$ which is moving along with the protons. What fields would be measured in $F^{\prime \prime}$ \} For this problem you may assume that the rest energy of a proton is $10^{9} \mathrm{cv}$.
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