00:01
Hello student to solve this question for part a we need to calculate the equivalent resistance so for that let us use the series resistance for here r1 plus r3 r1 plus r3 so putting the value of r1 and r3 we get the series resistance r1 is 13 plus r3 is 12 so it will give us 25 oms now for the parallel resistance rp 1 by rp will be equal to this rs 1 by r s plus the resistance that is connected in parallel r2, 1 by r2.
00:38
So putting the values we get 1 by 25 plus 1 by r2 is 18.
00:44
So from here, rp that is calculated as 10 .47 oms.
00:53
Now that we have calculated rp as well as rs, now we are left with only resistance r4.
01:00
So the equivalent resistance here will be equal to r equivalent equals rp plus r4.
01:08
So putting the values, we get 10 .47 plus r4 is 17.
01:13
So it will become 27 .47 oms.
01:19
So the final answer for part a, that is the equivalent resistance are equivalent will be equal to 27 .47 oms.
01:29
Now for part b we need to calculate the current through resistance r4.
01:36
For that, let us write the formula for current which will be equal to i4 equals v divided by r equivalent...