00:01
In the given circuit, find the value of zl that will absorb the maximum power and the value for this maximum power is.
00:13
Then the circuit is to find the thavenin's impedance zth, connect 1 ampere current source between the low terminals by replacing the voltage with a short circuit.
00:30
Then from this circuit, the node voltage v1 equals to v0.
00:35
Applying the kirchhoff's voltage law, the v1 voltage is here and v2 is at this node.
00:46
Applying kcl law at the node v1, we can write v1 by 1 plus v1 by j plus v1 minus v2 by minus j equals 0.
00:58
Substitute v0 for v1 the reduced form of this equation will be v0 j v2 this is equation one now applying k c loyd the node v2 v2 v2 minus v1 by minus j minus 2 v0 minus 1 equals 0 from here we can write jv2 minus jv1 minus jv1 minus jv1 minus 2 v0 minus 1 equals 0 substitute here again v0 for 1 the equation will be reduced to jv1 jv1 v2 minus 2 plus j v0 equals 1.
01:35
Using equation 1 in here, that is substituting value for v0, from here the value for v2 comes out to be 1 by 1 minus j, which we can write 0 .5 plus j 0 .5 volt.
01:53
Now calculating the thhevnin equivalent impedance j -th equals v2 by 1 ampere, 0 .5 plus j 0 .5 divided by 1, which is again 0 .5 plus j 0 .5 o.
02:12
For maximum power transfer to the load, load impedance must be equals to the complex conjugate of the theranine impedance.
02:32
That is, zl must be equals to the conjugate...