E = 100 V \angle 0^\circ R_1 4 \Omega I_1 I_2 R_2 9 \Omega X_L = 6 \Omega X_C 7 \Omega R_3 8 \Omega
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We have R = 4Ω and Xc = 70Ω. Since Xc is the reactance of a capacitor, we can use the formula Xc = 1/(2πfC), where f is the frequency and C is the capacitance. However, since we don't have the frequency or capacitance values, we cannot calculate Xc accurately. Show more…
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