00:01
E1 is equal to 29 .1v, e2 is equal to 45 .8v, r1 is equal to 1 .6 ohms, r2 is also equal to 1 .6 ohms, r3 is equal to 6 .1 ohms, r4 is equal to 12 .7 ohms, rl is equal to 5 .1 ohms.
00:30
Applying kvl rule to the first loop, we have e1 is equal to e1 minus current i1, r1 minus r3 into i1 minus il.
00:47
This is equal to 0.
00:49
Substitute the values 29 .1 minus 7 .7 i1 plus 6 .1 il.
00:59
This is equal to 0.
01:01
Let this be equation 1.
01:03
Applying kvl rule to the second loop, we have il, rl plus r4 times il plus i2 minus r3 i1 minus il equal to 0.
01:26
Substitute the values in this equation and we have 23 .9 il minus 6 .1 i1 plus 12 .7 i2.
01:38
This is equal to 0.
01:39
Let this be equation 2...