In the circuit shown; the 16.0-V battery is removed and reinserted with the opposite polarity; so that its negative terminal is now next to point a. The current (in A) in the circuit is 16.0 V 5.0 Ω 9.0 Ω 8.0 V 1.41 0.47 2 3
Added by William M.
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This means that the direction of the current in the circuit will also be reversed. Show more…
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