In the circuit shown, the switch is initially at the closed position and has been there for a long time. At time ( t=0 ), the switch moves to the open position. The component values in the circuit are given by ( R_{1}=10 mathrm{k} Omega, R_{2}=8 mathrm{k} Omega, R_{3}=8 mathrm{k} Omega ), and ( L=54 mathrm{mH} ), and the source current is ( I_{s}=96 mathrm{~mA} ). If the inductor voltage is defined with + on the top and - on the bottom of the inductor, what is the value of the inductor voltage at the time instant immediately after the switch moves, ( V_{L}left(0^{+} ight) ). Enter your answer in units of Volts.
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Since the switch has been closed for a long time, the inductor behaves like a short circuit. The current through the inductor is the same as the current through \( R_3 \). Show more…
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