Question

In the diagram, \( \mathrm{BA}=\mathrm{BE}, \overline{\mathrm{BE}} \| \overline{\mathrm{CD}} \) and \( \mathrm{m} \angle \mathrm{ACD}=56^{\circ} \). Find \( \mathrm{m} \angle \mathrm{BAE} \). \( 56^{\circ} \) \( 62^{\circ} \) \( 68^{\circ} \) \( 124^{\circ} \) None of these

          In the diagram, \( \mathrm{BA}=\mathrm{BE}, \overline{\mathrm{BE}} \| \overline{\mathrm{CD}} \) and \( \mathrm{m} \angle \mathrm{ACD}=56^{\circ} \). Find \( \mathrm{m} \angle \mathrm{BAE} \).
\( 56^{\circ} \)
\( 62^{\circ} \)
\( 68^{\circ} \)
\( 124^{\circ} \)
None of these

In the diagram, BA=BE, BECD and m∠ACD=56^∘. Find m∠BAE.
56^∘
62^∘
68^∘
124^∘
None of these

Added by Wesley J.

Geometry

Edward Burger, David J. Chard,Earlene J.… 1st Edition

Chapter 5

Instant Answer

Solved by Expert Jill Tolbert

Step 1

We have a geometric figure where \( \mathrm{BA}=\mathrm{BE} \), which implies that triangle \( \mathrm{ABE} \) is isosceles with \( \mathrm{BA} \) and \( \mathrm{BE} \) being the equal sides. Also, \( \overline{\mathrm{BE}} \| \overline{\mathrm{CD}} \), meaning Show more…

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In the diagram, \( \mathrm{BA}=\mathrm{BE}, \overline{\mathrm{BE}} \| \overline{\mathrm{CD}} \) and \( \mathrm{m} \angle \mathrm{ACD}=56^{\circ} \). Find \( \mathrm{m} \angle \mathrm{BAE} \). \( 56^{\circ} \) \( 62^{\circ} \) \( 68^{\circ} \) \( 124^{\circ} \) None of these