Question

In the drawings below, "CO" represents a carbonyl group (C=O). Which ester below will not form a beta-ketoester upon treatment with an alkoxide, followed by acidification of the reaction mixture? O (CH$_3$)$_2$CH-CO-O-CH$_3$ O CH$_3$-CH$_2$-CH$_2$-CO-O-CH$_3$ O CH$_3$-CO-O-CH(CH$_3$)$_2$ O CH$_3$-CH$_2$-CO-O-CH$_2$-CH$_3$

Name: in the drawings below co represents a carbonyl group co which ester below will not form a beta ketoester upon treatment with an alkoxide followed by acidification of the reaction mixture o c 54786
Uploaded: 2021-08-20T18:53:05-08:00
Duration: 1 min 30 s
Channel: Sima Sarker
Description: in the drawings below co represents a carbonyl group co which ester below will not form a beta ketoester upon treatment with an alkoxide followed by acidification of the reaction mixture o c 54786

          In the drawings below, "CO" represents a carbonyl group (C=O).
Which ester below will not form a beta-ketoester upon
treatment with an alkoxide, followed by acidification of
the reaction mixture?
O (CH$_3$)$_2$CH-CO-O-CH$_3$
O CH$_3$-CH$_2$-CH$_2$-CO-O-CH$_3$
O CH$_3$-CO-O-CH(CH$_3$)$_2$
O CH$_3$-CH$_2$-CO-O-CH$_2$-CH$_3$

in the drawings below co represents a carbonyl group co which ester below will not form a beta ketoester upon treatment with an alkoxide followed by acidification of the reaction mixture o c 54786

Added by James F.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sima Sarker

08/20/2021

Step 1

The reaction requires an $\alpha$-hydrogen on at least one of the carbonyl compounds. Show more…

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In the drawings below, "CO" represents a carbonyl group (C=O). Which ester below will not form a beta-ketoester upon treatment with an alkoxide, followed by acidification of the reaction mixture? O (CH$_3$)$_2$CH-CO-O-CH$_3$ O CH$_3$-CH$_2$-CH$_2$-CO-O-CH$_3$ O CH$_3$-CO-O-CH(CH$_3$)$_2$ O CH$_3$-CH$_2$-CO-O-CH$_2$-CH$_3$