In the figure, €1 - 2.78 V, Ez = 1.38 V, R1 = 4.220 Ω, Rz = 2.050 Ω, R3 = 4.980 Ω, and both batteries are ideal. What is the rate at which energy is dissipated in (a) R1, (b) Rz, and (c) Rz? What is the power of (d) battery and (e) battery 2?
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Total voltage = E1 - Ez = 2.78 V - 1.38 V = 1.4 V Total resistance = R1 + Rz + R3 = 4.220 Ω + 2.050 Ω + 4.980 Ω = 11.25 Ω Using Ohm's Law, I = V/R = 1.4 V / 11.25 Ω = 0.1244 A Show more…
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