00:01
Hi, here in this given problem, this is the vertical wall at which this is the horizontal beam whose right end is attached with the wall with the help of a cable.
00:23
Weight of this beam, uniform beam it is, so its weight will be acting exactly in the middle.
00:33
And this weight is given as 520 newton.
00:48
Its length, total length of this beam, this is 2 .6 meter.
00:57
Tension in this cable, this is given as maximum tension, 1400 newton.
01:10
So, we have to find the distance d at which this cable should be tied so that it may have this much tension, means tension equal to 1 ,400 newton, for which we will resolve this tension into two components, vertical before which we assume this angle to be theta.
01:36
So now vertical component here, this will be t sine theta...