In the figure what magnitude of force f applied horizontally...

In the figure, what magnitude of force F→ applied horizontally at the axle of the wheel is necessary to raise the wheel over an obstacle of height h = 0.172 m? The wheel's radius is r = 0.600 m and its mass is m = 0.813 kg.

Transcript

00:01 In this problem, we have been given that there is a wheel and the radius of this wheel is given as 0 .6 meter.

00:09 Also here, the mass of this wheel is given as 0 .813 kilograms.

00:16 And we need to determine the magnitude of the force that's applied horizontally at the axle.

00:23 So here, this is the axle about which the wheel is rotating.

00:26 And the force that's applied here is f, which we need to determine here.

00:32 And it's given that the vertical height through which the wheel has to be raised up is 0 .172 meters.

00:41 So here, in order to figure out the applied force, we see that this is the point which can be considered as a pivot about which the wheel will rotate and cross this vertical height.

00:54 So in order to figure out the total moment about this point, which should be just sufficient enough provided by the applied force, so that it crosses this vertical height, we observed that there are two forces that's acting on this wheel.

01:08 One is the weight, which is acting in the downward direction, and the other one is the applied force.

01:14 So we determine the torque because of the applied force, so that will be the magnitude of the force times the perpendicular distance from the pivot.

01:24 So we can definitely determine this perpendicular distance because this is the radius and we have been given this vertical height.

01:32 So this perpendicular distance will be equal to 0 .6 minus 0 .172 meters...

Question

In the figure, what magnitude of force F→ applied horizontally at the axle of the wheel is necessary to raise the wheel over an obstacle of height h = 0.172 m? The wheel's radius is r = 0.600 m and its mass is m = 0.813 kg.

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