00:01
For this problem on the topic of equilibrium and elasticity, we're told that a constant force is being applied horizontally at the axle of the wheel, as shown in the diagram, and this force allows the wheel to be raised over a step with a height of h is equal to 3 centimeters.
00:18
We are given the wheel's radius to be 6 centimeters, and the mass of the wheel to be 0 .8kg, and we want to calculate the magnitude of this constant force that is applied.
00:28
So as the wheel is raised over the obstacle, the only forces acting are the force f, which is applied horizontally at the axle, the force of gravity, mg, which acts vertically downward at the center of the wheel, as well as the force of the step corner, which is shown in the diagram as two components, fh and fv.
00:50
If the minimum force is applied, the wheel does not accelerate, so both the total force and the total torque acting on it are zero...