Question

In the ideal ramjet, the flow from the freestream (a) through the inlet is shock-free, adiabatic, and reversible; hence it is isentropic. The flow enters the combustor (2) where fuel is burnt at constant pressure to increase its stagnation enthalpy. A converging-diverging nozzle is used downstream of the combustor to accelerate the combustion products to supersonic speed at the exit of the nozzle (6). The "ideal" ramjet also presumes 1D isentropic flow from the combustor exit (4) through the nozzle exit (6). Due to these ideal process simplifications, stagnation pressure p0 is constant throughout. To further simplify the problem, assume constant properties, Cp = 1.0 kJ/kg-K and γ = 1.4. a. Use the momentum conservation equation with a CV analysis to derive an equation for thrust. All terms in the momentum balance should be clearly shown in a neat sketch of the CV. Let the inlet area of the ramjet be Ai, and the exit be Ae. Unlike the simple rocket thruster problem, the momentum inflow term is significant and should be included in the analysis. For this problem, you may want to consider changing the frame of reference to a "free-jet" configuration, where the ramjet is held fixed by a restraining force and a large jet of air with the freestream properties is directed onto the inlet, as if the ramjet is in a wind tunnel, except with no walls. b. The ramjet flies at an altitude of 60,000 ft and flight M = 2.5. i. Report (again) ambient pressure and temperature, pa and Ta. Use the compressible flow equations to calculate the free-stream properties stagnation temperature T0a, and stagnation pressure p0a. Calculate the free-stream velocity ua. ii. Use flow ma = 1.0 kg/s as a basis, and calculate the amount of heat required to increase the temperature in the combustor to T04 = 1800 K. Combustion takes place at "constant pressure." iii. The flow is accelerated in a converging-diverging nozzle to exit Mach number Me = 2.5. Use the compressible flow equations to calculate exit properties pe, Te, and ue. iv. Use part b values with the thrust equation from part a to calculate the "specific thrust," i.e., the thrust based on air flow ma = 1.0 kg/s.

          In the ideal ramjet, the flow from the freestream (a) through the inlet is shock-free, adiabatic, and reversible; hence it is isentropic. The flow enters the combustor (2) where fuel is burnt at constant pressure to increase its stagnation enthalpy. A converging-diverging nozzle is used downstream of the combustor to accelerate the combustion products to supersonic speed at the exit of the nozzle (6). The "ideal" ramjet also presumes 1D isentropic flow from the combustor exit (4) through the nozzle exit (6).

Due to these ideal process simplifications, stagnation pressure p0 is constant throughout. To further simplify the problem, assume constant properties, Cp = 1.0 kJ/kg-K and γ = 1.4.

a. Use the momentum conservation equation with a CV analysis to derive an equation for thrust. All terms in the momentum balance should be clearly shown in a neat sketch of the CV. Let the inlet area of the ramjet be Ai, and the exit be Ae. Unlike the simple rocket thruster problem, the momentum inflow term is significant and should be included in the analysis. For this problem, you may want to consider changing the frame of reference to a "free-jet" configuration, where the ramjet is held fixed by a restraining force and a large jet of air with the freestream properties is directed onto the inlet, as if the ramjet is in a wind tunnel, except with no walls.

b. The ramjet flies at an altitude of 60,000 ft and flight M = 2.5.
i. Report (again) ambient pressure and temperature, pa and Ta. Use the compressible flow equations to calculate the free-stream properties stagnation temperature T0a, and stagnation pressure p0a. Calculate the free-stream velocity ua.
ii. Use flow ma = 1.0 kg/s as a basis, and calculate the amount of heat required to increase the temperature in the combustor to T04 = 1800 K. Combustion takes place at "constant pressure."
iii. The flow is accelerated in a converging-diverging nozzle to exit Mach number Me = 2.5. Use the compressible flow equations to calculate exit properties pe, Te, and ue.
iv. Use part b values with the thrust equation from part a to calculate the "specific thrust," i.e., the thrust based on air flow ma = 1.0 kg/s.
        
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in the ideal ramjet the flow from the freestream a through the inlet is shock free adiabatic and reversible hence it is isentropic the flow enters the combustor 2 where fuel is burnt at cons 67402

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University Physics with Modern Physics
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Hugh D. Young 14th Edition
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In the ideal ramjet, the flow from the freestream (a) through the inlet is shock-free, adiabatic, and reversible; hence it is isentropic. The flow enters the combustor (2) where fuel is burnt at constant pressure to increase its stagnation enthalpy. A converging-diverging nozzle is used downstream of the combustor to accelerate the combustion products to supersonic speed at the exit of the nozzle (6). The "ideal" ramjet also presumes 1D isentropic flow from the combustor exit (4) through the nozzle exit (6). Due to these ideal process simplifications, stagnation pressure p0 is constant throughout. To further simplify the problem, assume constant properties, Cp = 1.0 kJ/kg-K and γ = 1.4. a. Use the momentum conservation equation with a CV analysis to derive an equation for thrust. All terms in the momentum balance should be clearly shown in a neat sketch of the CV. Let the inlet area of the ramjet be Ai, and the exit be Ae. Unlike the simple rocket thruster problem, the momentum inflow term is significant and should be included in the analysis. For this problem, you may want to consider changing the frame of reference to a "free-jet" configuration, where the ramjet is held fixed by a restraining force and a large jet of air with the freestream properties is directed onto the inlet, as if the ramjet is in a wind tunnel, except with no walls. b. The ramjet flies at an altitude of 60,000 ft and flight M = 2.5. i. Report (again) ambient pressure and temperature, pa and Ta. Use the compressible flow equations to calculate the free-stream properties stagnation temperature T0a, and stagnation pressure p0a. Calculate the free-stream velocity ua. ii. Use flow ma = 1.0 kg/s as a basis, and calculate the amount of heat required to increase the temperature in the combustor to T04 = 1800 K. Combustion takes place at "constant pressure." iii. The flow is accelerated in a converging-diverging nozzle to exit Mach number Me = 2.5. Use the compressible flow equations to calculate exit properties pe, Te, and ue. iv. Use part b values with the thrust equation from part a to calculate the "specific thrust," i.e., the thrust based on air flow ma = 1.0 kg/s.
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Transcript

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00:01 Hello students, let's solve this question.
00:02 This is a compression process on ts diagram.
00:08 So as compression is a reversible adiabatic process, we can write p into v raised to gamma is equal to a constant or p1 into v1 into gamma is equal to p2 into v2 gamma.
00:22 Therefore, p1 divided by p2 is equal to v2 divided by v1 the whole raised to gamma it will be equal to t1 divided by t2 the whole raised to gamma divided by gamma minus 1.
00:35 And we can write it as t2 divided by t1 is equal to p2 divided by p1 the whole raised to gamma minus 1 divided by gamma.
00:44 So this is a governing equation and we can say that p2 by p1 this is a pressure ratio that can be taken as r and t2 is equal to t1 into r in raised to gamma minus 1 divided by gamma and the value for gamma is 1 .4 for an adiabatic index.
01:08 Now for the first process that is 1 to 2 it is isotropic.
01:14 We can say that t1 value is 288 kelvin and r is equal to 45.
01:22 Let's substitute this into the equation of t2 it will be 288 into 45 raised to 1 .4 minus 1 divided by 1 .4.
01:34 Therefore, we will get t2 value is equal to 854 .552 kelvin...
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