00:01
All right, so we're told that we have the molecule p -o -b -r -3.
00:05
Phosphorus is a central atom, and first we want to draw a lewis structure in which there's no non -zero formal charges.
00:12
So we have phosphorus in the center, and we know that we're going to have at least one bond to each of these species, br, br, and br, like that.
00:25
So bromine tends to typically form one bond.
00:28
So if we were to put the other three loan pairs on it to satisfy its octet rule, now it has seven electrons.
00:35
So each of these bromines has a formal charge of zero.
00:39
Now, phosphorus wants to have five electrons, and right here it has only four.
00:45
So this way it has a formal charge.
00:48
So that means if we were to draw another bond to the oxygen, because we don't want to mess with bromine.
00:52
Bromine tends to form one bond each.
00:55
Now phosphorus has a formal charge of zero.
00:57
And then this oxygen has two bonds, so it would need two loan pairs in order to satisfy the octet rule.
01:04
And that way it has two from the bond and four loan, a total of six electrons belonging to it.
01:09
So a zero formal charge.
01:11
This is an example of an expanded octet, which is possible for the central phosphorus because it's in the third or below period.
01:19
So it has deorbital's available for expanded octet bonding, meaning more than four bonds around it...