Question

Using the size of the different types given in the table below, how much memory (in bytes) does this program have allocated for storing data after the code between Q1 and Q4 has run (the code after Q4 hasn't run yet)? Data Type | Size in bytes ---|--- char | 1 int | 4 pointer | 8

          Using the size of the different types given in the table below, how much memory (in bytes) does this program have allocated for storing data after the code between Q1 and Q4 has run (the code after Q4 hasn't run yet)?

Data Type | Size in bytes
---|---
char | 1
int | 4
pointer | 8

Using the size of the different types given in the table below, how much memory (in bytes) does this program have allocated for storing data after the code between Q1 and Q4 has run (the code after Q4 hasn't run yet)?

Data Type | Size in bytes
—|—
char | 1
int | 4
pointer | 8

Added by Joe M.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Akash M

05/26/2023

Step 1

Each integer takes 4 bytes. So, the total memory allocated for these integers is \(2 \times 4 = 8\) bytes. Show more…

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```c #include <stdlib.h> int main(void) { // Q1 int count = 1; int number; int *ptr = &count; int *ptr2 = &number; // Q2 ptr = ptr2; *ptr2 = 3; // Q3 ptr = malloc(number * sizeof(char)); // Q4 ptr2 = malloc(count * sizeof(char)); ptr = ptr2; } ```