00:01
Hello, here we have to solve the given assignment of three sub -questions.
00:04
Let's start with question one.
00:07
And first we have to calculate the energy loss due to the friction in one revolution.
00:14
So the track here, the particle has a mass of 0 .499 kilograms, and the track has a radius of 1 .27 meters.
00:30
The particle is given an initial speed of 7 .69 meters per second and after one revolution, its speed decreases to some v -final, let's say, v -final, that is 6 .28 meters per second.
00:49
And so it means that the initial kinetic energy equals to kinetic energy after the first revolution, so let's label it as some key final plus absolute work.
01:03
Done by the friction force.
01:06
Here, absolute work done by the friction force equals to coefficient of friction.
01:14
Actually, we need to calculate coefficient of friction later.
01:20
So now let's just calculate this energy loss.
01:23
So let's calculate this delta e, bc equals to the absolute value of work of the friction force.
01:29
And that equals to the initial kinetic energy minus final kinetic energy.
01:35
That equals to m over 2 times v initial squared minus v final squared.
01:45
That equals to 0 .499 kilograms over 2 times 7 .69 squared minus 6 .28 squared meters per second, which is squared.
02:00
Let's complete this calculation.
02:33
That equals to 4 .91 jule...