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Instruction. Show all your work for full credit. Partial credit will be awarded for a substantial progress on a problem. 1. (12 points) Let R be the region bounded by the curves $y = x^2$ and $y = 3x$. Calculate the following quantities. 10f Y (3,9) a) The area of R. Answer b) The volume obtained by rotating R about the x-axis. Answer c) The volume obtained by rotating R about the y-axis. Answer 2. (4 points) The engine of a bus exerts a force $F(x) = 3000 - 2x$ pounds on the bus when it has gone x feet from its starting point. How much work does the engine do on the bus in the first 1000 feet? d$w = F \cdot dx$ $\int_{0}^{1000} dw = \int_{0}^{1000} (3000 - 2x) dx$ $w = [3000x - \frac{2x^2}{2}]_{0}^{1000}$ $= [(3000 \times 1000 - (1000)^2) - (0 - 0)]$ $w = 2 \times 10^6 lb \cdot ft$ Answer $2 \times 10^6 lb \cdot ft$ 3. (4 points) Records indicate that t hours past midnight, the temperature at the local airport was $P(t) = -0.1t^2 + t + 50$ degrees Fahrenheit. What was the average temperature at the airport between 9 AM and noon? Answer 1

          Instruction. Show all your work for full credit. Partial credit will be awarded for a substantial
progress on a problem.
1.
(12 points) Let R be the region bounded by the curves $y = x^2$ and $y = 3x$. Calculate the
following quantities.
10f Y
(3,9)
a) The area of R.
Answer
b) The volume obtained by rotating R about the x-axis.
Answer
c) The volume obtained by rotating R about the y-axis.
Answer
2.
(4 points) The engine of a bus exerts a force $F(x) = 3000 - 2x$ pounds on the bus when
it has gone x feet from its starting point. How much work does the engine do on the bus in the
first 1000 feet?
d$w = F \cdot dx$
$\int_{0}^{1000} dw = \int_{0}^{1000} (3000 - 2x) dx$
$w = [3000x - \frac{2x^2}{2}]_{0}^{1000}$
$= [(3000 \times 1000 - (1000)^2) - (0 - 0)]$
$w = 2 \times 10^6 lb \cdot ft$
Answer
$2 \times 10^6 lb \cdot ft$
3.
(4 points) Records indicate that t hours past midnight, the temperature at the local airport
was
$P(t) = -0.1t^2 + t + 50$
degrees Fahrenheit. What was the average temperature at the airport between 9 AM and noon?
Answer
1
        
Show more…
Instruction. Show all your work for full credit. Partial credit will be awarded for a substantial
progress on a problem.
1.
(12 points) Let R be the region bounded by the curves y = x^2 and y = 3x. Calculate the
following quantities.
10f Y
(3,9)
a) The area of R.
Answer
b) The volume obtained by rotating R about the x-axis.
Answer
c) The volume obtained by rotating R about the y-axis.
Answer
2.
(4 points) The engine of a bus exerts a force F(x) = 3000 - 2x pounds on the bus when
it has gone x feet from its starting point. How much work does the engine do on the bus in the
first 1000 feet?
dw = F · dx
∫0^1000 dw = ∫0^1000 (3000 - 2x) dx
w = [3000x - (2x^2)/(2)]0^1000
= [(3000 × 1000 - (1000)^2) - (0 - 0)]
w = 2 × 10^6 lb · ft
Answer
2 × 10^6 lb · ft
3.
(4 points) Records indicate that t hours past midnight, the temperature at the local airport
was
P(t) = -0.1t^2 + t + 50
degrees Fahrenheit. What was the average temperature at the airport between 9 AM and noon?
Answer
1

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Instructions: Show all your work for full credit. Partial credit will be awarded for a substantial progress on a problem. 1. 12 points Let R be the region bounded by the curves y=x and y=3x. Calculate the following quantities: a) The area of R. Answer: b) The volume obtained by rotating R about the x-axis. Answer: c) The volume obtained by rotating R about the y-axis. Answer: 2. 4 points The engine of a bus exerts a force Fx=3000-2x pounds on the bus when it has gone x feet from its starting point. How much work does the engine do on the bus in the first 1000 feet? dwF.dx [c30ox100o-la-o-0 .0 w=2xllbP Answer: 3. 4 points Records indicate that t hours past midnight, the temperature at the local airport was Pt=-0.1t+t+50 degrees Fahrenheit. What was the average temperature at the airport between 9 AM and noon? Answer:
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Transcript

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00:01 In this problem we have to find the centroid of area of bounded reason.
00:06 Area of bounded reason.
00:16 Okay, it's centroid.
00:18 So to find this, we have to find the area of, first of minus minus y minus four is equals to x square.
00:31 Here, x is greater than and less than greater than 0 less than 2.
00:39 Y is greater than 0 and less than 4.
00:43 Okay.
00:44 So for the area, we will integrate limit a to b.
00:50 Function of x into dx is equals to limit 0 to 2 and our function is 4 minus x square d x.
01:03 So area will be 4 minus x squared.
01:04 So, area will be 4 minus x squared.
01:08 So 4x minus x cubed by 3 raised to the power limit 0 to 2 so that is equals to 8 minus 8 by 3 so our area is 16 by 3 okay now x intercept of centroid that is 1 by a integration limit 0 to 2 x fx into d x now 1 by a integration limit 0 to 2 x into function of x that is 4 minus x square into d x so 1 by a into we will integrate this so 4 into 2 square by 2 we have take the limit 2 minus x raised to the power 4 by 4 limit 0 2...
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