\( \int \frac{5 x+8}{(x+1)^{2}(2-x)} d x \)
Added by Steven D.
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The denominator is already factored as \((x+1)^2(2-x)\), so we set up the decomposition as follows: \[ \frac{5x+8}{(x+1)^2(2-x)} = \frac{A}{x+1} + \frac{B}{(x+1)^2} + \frac{C}{2-x} \] Show more…
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