Question

9. \int \frac{x dx}{\sqrt{9 - x^2}} = \\ (a) \frac{1}{2}\sqrt{9 - x^2} + C \\ (b) \frac{1}{2}sin^{-1}(x/2) + C \\ (c) -2\sqrt{9 - x^2} + C \\ (d) -\sqrt{9 - x^2} + C \\ (e) None of the above.

          9. \int \frac{x dx}{\sqrt{9 - x^2}} = \\
(a) \frac{1}{2}\sqrt{9 - x^2} + C \\
(b) \frac{1}{2}sin^{-1}(x/2) + C \\
(c) -2\sqrt{9 - x^2} + C \\
(d) -\sqrt{9 - x^2} + C \\
(e) None of the above.

9. ∫(x dx)/(√(9 - x^2)) =

(a) (1)/(2)√(9 - x^2) + C

(b) (1)/(2)sin^-1(x/2) + C

(c) -2√(9 - x^2) + C

(d) -√(9 - x^2) + C

(e) None of the above.

Added by Tiffany Q.

Calculus: Early Transcendentals

James Stewart 8th Edition

Thanks for your feedback!

int (xdx)/(sqrt(9-x^(2)))= (a) (1)/(2)sqrt(9-x^(2))+C (b) (1)/(2)sin^(-1)((x)/(2))+C (c) -2sqrt(9-x^(2))+C (d) -sqrt(9-x^(2))+C (e) None of the above. xdx aV9-x2+C (bsin-1x/2)+C c-29-x2+O d-9-x2+C (e) None of the above

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