( int_{1}^{2} int_{0}^{1} int_{0}^{x^{4}} 5 z e^{-x^{5}} d y d x d z )
Added by Edna P.
Close
Step 1
Since the integrand does not contain y, the integral is simply the integrand times the length of the interval from 0 to \(x^4\), which is \(x^4\). So, we have: \( \int_{1}^{2} \int_{0}^{1} 5z x^4 e^{-x^{5}} dx dz \) Show more…
Show all steps
Your feedback will help us improve your experience
Breanna Ollech and 50 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
$$ \int_{2}^{2+i x} x e^{i z} d z $$
FUNCTIONS OF A COMPLEX VARIABLE
Contour integrals
Evaluate $\int_{0}^{2} \mathrm{~d} x \int_{1}^{3} \mathrm{~d} y \int_{1}^{2} x y^{2} z \mathrm{~d} z$
Multiple integrals
Further problems
Evaluate the integrals. $$\int_{0}^{1} \int_{0}^{1} \int_{0}^{1}\left(x^{2}+y^{2}+z^{2}\right) d z d y d x$$
Multiple Integrals
Triple Integrals in Rectangular Coordinates
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD