\int_1^6 f(x)dx - \int_1^4 f(x)dx = \int_a^b f(x)dx \text{ where } a = 0 \text{ and } b = 2
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Step 1: Rewrite the given equation using the properties of definite integrals: \int_1^6 f(x)dx - \int_1^4 f(x)dx = \int_a^b f(x)dx Show more…
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