00:01
Hi, from the question given that here we need to integrate the function f of x, y, z is equal to 4z over the position of the plane x plus y plus z is equal to 5 that lies above the square 0 is less than or equal to x is less than or equal to 3 and 0 is less than or equal to y is less than or equal to 3 in the xy plane.
00:26
So here we need to find the integral double integral over the region s f of x, y, z ds.
00:34
So here z is equal to 5 minus x minus y and zx is equal to zy is equal to negative 1.
00:47
So this implies n is equal to 1 comma 1 comma 1.
00:55
Now the absolute value of n is square root of 3.
01:00
Now ds is equal to ds is equal to root 3 da.
01:09
So that the required integral integral x varies from 0 to 3, y varies from 0 to 3 root 3 times of 6 times z is 5 minus x minus y dy dx.
01:28
So in the given question it is not 6 it is 4.
01:34
So which is equal to 4 root 3 times integral 0 to 3 integral 0 to 3 5 minus x minus y dy dx.
01:47
So 4 root 3 integral 0 to 3...